Let the system of linear equations  $x+y+k z=2$ ;  $2 x+3 y-z=1$ ; $3 x+4 y+2 z=k$ , have infinitely many solutions. Then the system $( k +1) x +(2 k -1) y =7$ ; $(2 k +1) x +( k +5) y =10 \text { has : }$

  • [JEE MAIN 2023]
  • A

    infinitely many solutions

  • B

    unique solution satisfying $x-y=1$

  • C

    no solution

  • D

    unique solution satisfying $x+y=1$

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